0=8x^2+16x-7192

Solution for 0=8x^2+16x-7192 equation:

0=8x^2+16x-7192

We move all terms to the left:

0-(8x^2+16x-7192)=0

We add all the numbers together, and all the variables

-(8x^2+16x-7192)=0

We get rid of parentheses

-8x^2-16x+7192=0

a = -8; b = -16; c = +7192;
Δ = b2-4ac
Δ = -162-4·(-8)·7192
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{230400}=480$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-480}{2*-8}=\frac{-464}{-16}
=+29
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+480}{2*-8}=\frac{496}{-16}
=-31
$